The arc Length For A Vector Function And it's Derivative

The arc length formula for a curve defined using parametric functions \(x(t)\) and \(y(t)\) between \(t=b\) and \(t=a\) is:

\[ L = \int_a^b \sqrt{x'(t)^2 + y'(t)^2} \ dt \]

Let \(\textbf{r}(t) = y(t)\textbf{i} + x(t)\textbf{j}\). The arc length made traced by \(\textbf{r}(t)\) between \(t=b\) and \(t=a\) is:

\[ s = \int_a^b \sqrt{x'(t)^2 + y'(t)^2} \ dt = \int_a^b \Vert \textbf{r}'(t) \Vert \ dt \]

This is assuming \(\textbf{r}(t)\) defines a smooth curve. If \(\textbf{r}(t)\) is three dimensional:

\[ s = \int_a^b \sqrt{x'(t)^2 + y'(t)^2 + z'(t)^2} \ dt = \int_a^b \Vert \textbf{r}'(t) \Vert \ dt\]

Suppose \(a\) is a constant and \(b\) is a variable, we can define the arc length function as:

\[ s(b) = \int_a^b \sqrt{x'(t)^2 + y'(t)^2 + z'(t)^2} \ dt = \int_a^b \Vert \textbf{r}'(t) \Vert \ dt\]

According to the Fundamental Theorem of Calculus:

\[ \frac{d}{db} s(b) = \Vert \textbf{r}'(b) \Vert \]

Styles

(uses cookies)