Proof That (ab)^m = (a^m * b^m)

\((ab)^m\) basically means:

\[ \overbrace{(ab) * (ab) * (ab) * \ldots}^{m} = \overbrace{a * b * a * b * a * b * \ldots}^{m}\]

We can group all the \(a\) together and all the \(b\) together. Each of them appear \(m\) times:

\[ \overbrace{a*a*a*\ldots}^{m} * \overbrace{b*b*b*\ldots}^{m} \]

This proves that \( (ab)^m = a^m * b^m\). This proof only works when \(m\) is an integer.

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